37- van der waals forces

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Van der Waals forces

Van der Waals force may be due to the entanglement of orbital e+-/e-+ and e-+/e+- particles existing at different energy levels in adjacent atoms.  These entangled orbital particles each possess significantly different rates of e-m interaction, but are in-phase (i.e., possess opposing e-m directionality) with each other.  This results in a weak entanglement or a weak bond.

Each of the  orbital e+-/e-+ particles is entangled with a nucelar e-+/e+- particle in their respective nuclei, possessing the same rate of e-m interaction, resulting in a strong entanglement.

Example of orbital e-+/e+- particles involved in creation of Van der Waals force: 

If particle A has 10 e-m interactions for every one e-m interaction of particle B, then particle B would experience entanglement with particle A with every e-m interaction, while particle A would only experience entanglement with particle B once out of every ten e-m interactions.  This means that particle A would not be entangled with particle B nine out of every ten e-m interactions, giving it greater opportunity to interact with other energy systems (possibly becoming disentangled from particle B) than if the two particles had the same rate of e-m interaction. 

Another possibility is that Particle A may also be entangled with up to nine other particles with the same slower rate of e-m interaction as Particle B.  In any case, the entangled relationship between Particle A and Particle B is a weak one, resulting in a weak bond between their respective atoms.

 

See illustration below. Click here for enlargement.

 

37- van der Waals forces

 

To explore traditional views on Van der Waals forces, see "Van der Waals force" on Wikipedia.